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This private method calculates the index position where the given value belongs in the list, that is, the index position where the value is (if it is in the list), or where it should go (if it isn t in the list) It computes the comparison key for the given value using the sorted list s key function, and compares the comparison key with the computed comparison keys of the items that the method examines The algorithm used is binary search (also called binary chop), which has excellent performance even on very large lists for example, at most, 21 comparisons are required to nd a value s position in a list of 1 000 000 items Compare this with a plain unsorted list which uses linear search and needs an average of 500 000 comparisons, and at worst 1 000 000 comparisons, to nd a value in a list of 1 000 000 items

def remove(self, value): index = self__bisect_left(value) if index < len(self__list) and self__list[index] == value: del self__list[index] else: raise ValueError("{0}remove(x): x not in list"format( self__class____name__))

Most programmers will never implement their own reductions because the reduction mechanisms available with most parallel programming environments meet their needs Java, however, does not provide a reduction operator, so Java programmers might need to implement their own parallel reductions In any case, the algorithms used for reductions are instructive and well worth the effort to understand

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This method is used to remove the rst occurrence of the given value It uses the SortedList__bisect_left() method to nd the index position where the value belongs and then tests to see whether that index position is within the list and that the item at that position is the same as the given value If the conditions are met the item is removed; otherwise, a ValueError exception is raised (which is what listremove() does in the same circumstances)

Some items can exist only as part of or when owned by another item Information must contain some number of characters

def remove_every(self, value): count = 0 index = self__bisect_left(value) while (index < len(self__list) and self__list[index] == value):

Figure 617 OpenMP program to time the execution of a function called runit() We use a reduction clause to find sum of the runtimes

Python s bisect module provides the bisectbisect_left() function and some others, but at the time of this writing none of the bisect module s functions can work with a key function

This method is similar to the SortedListremove() method, and is an extension of the list API It starts off by nding the index position where the rst occurrence of the value belongs in the list, and then loops as long as the index position is within the list and the item at the index position is the same as the given value The code is slightly subtle since at each iteration the matching item is deleted, and as a consequence, after each deletion the item at the index position is the item that followed the deleted item

#include <stdioh> #include <omph> // OpenMP include file extern void runit(); int main(int argc, char**argv) { int num_threads; // the number of processes in the group double ave_time=00; #pragma omp parallel reduction(+ : ave_time) num_threads(10) { double local_result; double time_init, time_final, time_elapsed; // The single construct causes one thread to set the value of // the num_threads variable The other threads wait at the // barrier implied by the single construct #pragma omp single num_threads = omp_get_num_threads(); time_init = omp_get wtime(); runit(); // a function that we wish to time on each process time_final = omp_get wtime(); time_elapsed = time_final - time_init; } ave_time += time_elapsed; ave_time = ave_time/(double)num_threads;

def count(self, value): count = 0 index = self__bisect_left(value) while (index < len(self__list) and self__list[index] == value): index += 1 count += 1 return count

Given a set of similar data, no one piece of information is required, but at least one of the set is required

This method returns the number of times the given value occurs in the list (which could be 0) It uses a very similar algorithm to SortedListremove_ every(), only here we must increment the index position in each iteration

def index(self, value): index = self__bisect_left(value) if index < len(self__list) and self__list[index] == value: return index raise ValueError("{0}index(x): x not in list"format( self__class____name__))

printf(" ave time (secs): % \n", ave_time); return 0; }

Since a SortedList is ordered we can use a fast binary search to nd (or not nd) the value in the list

def __delitem__(self, index): del self__list[index]

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