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IF OBJECT_ID('dbo.RoadsTC') IS NOT NULL DROP FUNCTION dbo.RoadsTC; GO CREATE FUNCTION dbo.RoadsTC() RETURNS @RoadsTC TABLE ( uniquifier INT NOT NULL IDENTITY, from_city VARCHAR(3) NOT NULL, to_city VARCHAR(3) NOT NULL, distance INT NOT NULL, route VARCHAR(MAX) NOT NULL, PRIMARY KEY (from_city, to_city, uniquifier) ) AS BEGIN DECLARE @added AS INT; INSERT INTO @RoadsTC SELECT city1 AS from_city, city2 AS to_city, distance, '.' + city1 + '.' + city2 + '.' FROM dbo.Roads; SET @added = @@rowcount; INSERT INTO @RoadsTC SELECT city2, city1, distance, '.' + city2 + '.' + city1 + '.' FROM dbo.Roads;

Queues are the key to understanding how Service Broker works . At its lowest level, Service Broker puts messages on queues, takes messages off queues, or moves messages between queues . Most Service Broker problems turn out to be caused by messages being on the wrong queue . One of the most important sources of troubleshooting information is the transmission_status column of the sys.transmission_queue view . If the message has tried to leave the queue and failed, the transmission_status column will indicate what went wrong .

IF OBJECT_ID('dbo.T1') IS NOT NULL DROP TABLE dbo.T1; GO CREATE TABLE dbo.T1(col1 VARCHAR(5)); INSERT INTO dbo.T1(col1) VALUES('A'); INSERT INTO dbo.T1(col1) VALUES('A'); INSERT INTO dbo.T1(col1) VALUES('A'); INSERT INTO dbo.T1(col1) VALUES('B'); INSERT INTO dbo.T1(col1) VALUES('B'); INSERT INTO dbo.T1(col1) VALUES('C'); INSERT INTO dbo.T1(col1) VALUES('C'); INSERT INTO dbo.T1(col1) VALUES('C'); INSERT INTO dbo.T1(col1) VALUES('C'); INSERT INTO dbo.T1(col1) VALUES('C');

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SET @added = @added + @@rowcount; WHILE @added > 0 BEGIN INSERT INTO @RoadsTC SELECT DISTINCT TC.from_city, R.city2, TC.distance + R.distance, TC.route + city2 + '.' FROM @RoadsTC AS TC JOIN dbo.Roads AS R ON R.city1 = TC.to_city WHERE NOT EXISTS (SELECT * FROM @RoadsTC AS TC2 WHERE TC2.from_city = TC.from_city AND TC2.to_city = R.city2 AND TC2.distance <= TC.distance + R.distance) AND TC.from_city <> R.city2; SET @added = @@rowcount; INSERT INTO @RoadsTC SELECT DISTINCT TC.from_city, R.city1, TC.distance + R.distance, TC.route + city1 + '.' FROM @RoadsTC AS TC JOIN dbo.Roads AS R ON R.city2 = TC.to_city WHERE NOT EXISTS (SELECT * FROM @RoadsTC AS TC2 WHERE TC2.from_city = TC.from_city AND TC2.to_city = R.city1 AND TC2.distance <= TC.distance + R.distance) AND TC.from_city <> R.city1; SET @added = @added + @@rowcount; END RETURN; END GO

OPEN conv; FETCH NEXT FROM conv INTO @handle; WHILE @@FETCH_STATUS = 0 BEGIN END Conversation @handle WITH CLEANUP; FETCH NEXT FROM conv INTO @handle; END CLOSE conv; DEALLOCATE conv;

The function might return more than one row for the same source and target cities. To return shortest paths and distances, use the following query:

The solution must be compatible with SQL Server 2000, so you can't simply use the ROW_NUMBER function. Also, the solution must be standard.

If you remove the WHERE clause from the SELECT statement, this script will get rid of all conversations in the database . This script obviously requires administrator privileges to run and should be done only to clean up test data . It should never be done on a system with real dialogs running .

SELECT from_city, to_city, distance, route FROM (SELECT from_city, to_city, distance, route, RANK() OVER (PARTITION BY from_city, to_city ORDER BY distance) AS rk FROM dbo.RoadsTC()) AS RTC WHERE rk = 1;

The derived table query assigns a rank value (rk) to each row, based on from_city, to_city partitioning and distance ordering. This means that shortest paths are assigned with the rank value 1. The outer query lters only shortest paths (rk = 1). When you re done querying the RoadPaths table, don t forget to drop it:

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