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Public Sub Listing1_34() Dim numbers As Integer() = New Integer() {1, 3, 5, 7, 9} Dim firstDelegate As New Func(Of Integer, Boolean)(AddressOf firstFunc) Dim lastDelegate As New Func(Of Integer, Boolean)(AddressOf lastFunc) Dim query = numbers.FirstOrDefault(firstDelegate) Console.WriteLine("The first even element in the sequence") ObjectDumper.Write(query) Console.WriteLine("The last odd element in the sequence") query = numbers.LastOrDefault(lastDelegate) ObjectDumper.Write(query) End Sub

The solution consists of assuming values of and nding the ux densities Bk From the magnetization curves (Fig 1634), the corresponding Hk can be obtained The substitution of these values in Eq (16139) should yield the given M if the correct value of has been assumed Various values of are assumed until Eq (16139) is satis ed A special case arises when the series circuit has just two elements, one of which is iron with uniform ux density Bi and the other of which is an air gap having the same ux density (Ba Bi) Here Eq (16139) reduces to

There are times when there is no direct way of converting the value from one type to another, as in this example:

(16140a)

int x; x = SystemReadLine();

(16140b)

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SystemReadLine() returns a string, so even if we type in a number, the compiler would still not be able to assign the number (as a string) to the int variable x The solution is to do the following:

Equation (16140b) is the equation of a straight line in the two unknowns Hi and Bi The other equation involving these two unknowns is the magnetization curve of the iron Hence the required values of Bi and Hi are the coordinates of the point of intersection of the straight line [Eq (16140b)] and the magnetization curve (Fig 1634) Having determined Bi , the value of can be obtained from the expression Bi Ai , where Ai is the cross-sectional area of the iron Case B2: Given M, Required (Parallel Circuit) Referring to Fig 1635b,

(16141a) (16141b)

int x; x = Int32Parse(SystemReadLine());

Having obtained Hk , determine Bk from the magnetization curve and obtain from Bk Ak the relation Case B3: Given M, Required (Series-Parallel Circuit) The solution of this problem is accomplished by trial Thus various values of are assumed, and the corresponding values of the ux densities Bk are found Then from the magnetization curves the values Hk are determined The relation which must be satis ed by each branch of the series-parallel circuit is M Hkbk Conclusion It will be observed that the only magnetic circuits which possess a straightforward solution are those discussed under cases A1 and B2 The remaining circuits are solvable only by trial This emphasizes the difference between electric and magnetic circuits a difference which is, in a great measure, due to the fact

The magic in this code is that we use one of the primitive value types as a class (Int32 is the class that defines the 32-bit signed integer that C# uses as the int data type) The numeric classes from the Common Type System all have a Parse() method that will

that magnetic materials do not obey the law of ux superposition In other words, the magnetization curves (Fig 1634) are not straight lines

convert the string to the respective data type The conversion is pure magic, and one almost feels like calling out like Kim the Danish magician: Nothing up my sleeves and Wupti! The conversion is done The mechanics in this conversion make use of a feature in the C# language that seamlessly allows a data type to be switched from a value type to a reference type and back This is the boxing and unboxing process we mentioned in the introduction PART I

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